MATH SOLVE

2 months ago

Q:
# What is the equation of a line that passes through the point (9, β3) and is parallel to the line whose equation is 2xβ3y=6 ?Enter your answer in the box

Accepted Solution

A:

2x - 3y = 6

-3y = -2x + 6

y = 2/3x - 2....the slope here is 2/3. A parallel line will have the same slope

y = mx + b

slope(m) = 2/3

(9,-3)...x = 9 and y = -3

now we sub and find b, the y int

-3 = 2/3(9) + b

-3 = 6 + b

-3 - 6 = b

-9 = b

so ur parallel equation is : y = 2/3x - 9 <== or 2x -3y = 27

-3y = -2x + 6

y = 2/3x - 2....the slope here is 2/3. A parallel line will have the same slope

y = mx + b

slope(m) = 2/3

(9,-3)...x = 9 and y = -3

now we sub and find b, the y int

-3 = 2/3(9) + b

-3 = 6 + b

-3 - 6 = b

-9 = b

so ur parallel equation is : y = 2/3x - 9 <== or 2x -3y = 27