MATH SOLVE

3 months ago

Q:
# The mean of the scores obtained by a class of students on a physics test is 42. The standard deviation is 8%. Students have to score at least 50 to pass the test. Assuming that the data is normally distributed, % of the students passed the test.

Accepted Solution

A:

We'll need to determine the z-score for the case where the mean is 42, the std. dev. is 8% and the passing score 50. Then the area under the std. normal curve to the right of this z-score represents the # of students who pass.

50 - 42 8

z = ---------------- = ----- = 1

8 8

One way to answer this is to determine the area under the normal curve to the LEFT of z=1, and then subtract that area from 1.00.

Important fact: 68% of data values are found within 1 std. dev. of the mean; this means that 34% of data values are found between 0 and 1 std. dev.

Adding together the area under the normal curve to the left of z=0 (which is 0.50) and this 0.34 results in 0.84. 84% of students earned scores of less than 50. (100%-84%) of the students earned scores of greater than 50.

Thus, 16% passed, 84% failed.

50 - 42 8

z = ---------------- = ----- = 1

8 8

One way to answer this is to determine the area under the normal curve to the LEFT of z=1, and then subtract that area from 1.00.

Important fact: 68% of data values are found within 1 std. dev. of the mean; this means that 34% of data values are found between 0 and 1 std. dev.

Adding together the area under the normal curve to the left of z=0 (which is 0.50) and this 0.34 results in 0.84. 84% of students earned scores of less than 50. (100%-84%) of the students earned scores of greater than 50.

Thus, 16% passed, 84% failed.